What is the n factor of KMnO4 in acidic medium? Write the reaction involved.

 In acidic medium KMnO4 reduces to Mn+2.

8H+ + MnO4- + 5e( acidic medium)——→ Mn+2(aq)+ 4H2O

So clearly, from the above reaction, n-factor is 5

Hope you understood!!

Thank you.